0=2+6t-4.8t^2

Solution for 0=2+6t-4.8t^2 equation:

0=2+6t-4.8t^2

We move all terms to the left:

0-(2+6t-4.8t^2)=0

We add all the numbers together, and all the variables

-(2+6t-4.8t^2)=0

We get rid of parentheses

4.8t^2-6t-2=0

a = 4.8; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·4.8·(-2)
Δ = 74.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{74.4}}{2*4.8}=\frac{6-\sqrt{74.4}}{9.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{74.4}}{2*4.8}=\frac{6+\sqrt{74.4}}{9.6}
$